3.63 \(\int \frac{1}{\sqrt{a+b \cos ^2(x)}} \, dx\)

Optimal. Leaf size=42 \[ \frac{\sqrt{\frac{b \cos ^2(x)}{a}+1} F\left (x+\frac{\pi }{2}|-\frac{b}{a}\right )}{\sqrt{a+b \cos ^2(x)}} \]

[Out]

(Sqrt[1 + (b*Cos[x]^2)/a]*EllipticF[Pi/2 + x, -(b/a)])/Sqrt[a + b*Cos[x]^2]

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Rubi [A]  time = 0.0289905, antiderivative size = 42, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {3183, 3182} \[ \frac{\sqrt{\frac{b \cos ^2(x)}{a}+1} F\left (x+\frac{\pi }{2}|-\frac{b}{a}\right )}{\sqrt{a+b \cos ^2(x)}} \]

Antiderivative was successfully verified.

[In]

Int[1/Sqrt[a + b*Cos[x]^2],x]

[Out]

(Sqrt[1 + (b*Cos[x]^2)/a]*EllipticF[Pi/2 + x, -(b/a)])/Sqrt[a + b*Cos[x]^2]

Rule 3183

Int[1/Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2], x_Symbol] :> Dist[Sqrt[1 + (b*Sin[e + f*x]^2)/a]/Sqrt[a +
b*Sin[e + f*x]^2], Int[1/Sqrt[1 + (b*Sin[e + f*x]^2)/a], x], x] /; FreeQ[{a, b, e, f}, x] &&  !GtQ[a, 0]

Rule 3182

Int[1/Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2], x_Symbol] :> Simp[(1*EllipticF[e + f*x, -(b/a)])/(Sqrt[a]*
f), x] /; FreeQ[{a, b, e, f}, x] && GtQ[a, 0]

Rubi steps

\begin{align*} \int \frac{1}{\sqrt{a+b \cos ^2(x)}} \, dx &=\frac{\sqrt{1+\frac{b \cos ^2(x)}{a}} \int \frac{1}{\sqrt{1+\frac{b \cos ^2(x)}{a}}} \, dx}{\sqrt{a+b \cos ^2(x)}}\\ &=\frac{\sqrt{1+\frac{b \cos ^2(x)}{a}} F\left (\frac{\pi }{2}+x|-\frac{b}{a}\right )}{\sqrt{a+b \cos ^2(x)}}\\ \end{align*}

Mathematica [A]  time = 0.0641081, size = 46, normalized size = 1.1 \[ \frac{\sqrt{\frac{2 a+b \cos (2 x)+b}{a+b}} F\left (x\left |\frac{b}{a+b}\right .\right )}{\sqrt{2 a+b \cos (2 x)+b}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/Sqrt[a + b*Cos[x]^2],x]

[Out]

(Sqrt[(2*a + b + b*Cos[2*x])/(a + b)]*EllipticF[x, b/(a + b)])/Sqrt[2*a + b + b*Cos[2*x]]

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Maple [A]  time = 0.37, size = 48, normalized size = 1.1 \begin{align*} -{\frac{1}{\sin \left ( x \right ) }\sqrt{ \left ( \sin \left ( x \right ) \right ) ^{2}}\sqrt{{\frac{a+b \left ( \cos \left ( x \right ) \right ) ^{2}}{a}}}{\it EllipticF} \left ( \cos \left ( x \right ) ,\sqrt{-{\frac{b}{a}}} \right ){\frac{1}{\sqrt{a+b \left ( \cos \left ( x \right ) \right ) ^{2}}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a+b*cos(x)^2)^(1/2),x)

[Out]

-(sin(x)^2)^(1/2)*((a+b*cos(x)^2)/a)^(1/2)*EllipticF(cos(x),(-b/a)^(1/2))/sin(x)/(a+b*cos(x)^2)^(1/2)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{b \cos \left (x\right )^{2} + a}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*cos(x)^2)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/sqrt(b*cos(x)^2 + a), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{1}{\sqrt{b \cos \left (x\right )^{2} + a}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*cos(x)^2)^(1/2),x, algorithm="fricas")

[Out]

integral(1/sqrt(b*cos(x)^2 + a), x)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{a + b \cos ^{2}{\left (x \right )}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*cos(x)**2)**(1/2),x)

[Out]

Integral(1/sqrt(a + b*cos(x)**2), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{b \cos \left (x\right )^{2} + a}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*cos(x)^2)^(1/2),x, algorithm="giac")

[Out]

integrate(1/sqrt(b*cos(x)^2 + a), x)